mysql优化中如何进行IN换INNERJOIN
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今天撸代码时,遇到SQL问题:
要将A表查询的ID,匹配B表的ID,并将B表全部内容查询出来:
未优化前:
MySQL [xxuer]> SELECT -> COUNT(*) -> FROM -> t_cmdb_app_version -> WHERE -> id IN (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation); +----------+ | COUNT(*) | +----------+ | 266 | +----------+ 1 row in set (0.21 sec)
优化后:
MySQL [xxuer]> SELECT -> count(*) -> FROM -> t_cmdb_app_version a -> INNER JOIN -> (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation) b ON a.id = b.pid; +----------+ | count(*) | +----------+ | 266 | +----------+ 1 row in set (0.00 sec)
查看执行计划对比:
MySQL [xxuer]> explain SELECT -> COUNT(*) -> FROM -> t_cmdb_app_version -> WHERE -> id IN (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation); +----+--------------------+---------------------+-------+---------------+---------+---------+------+------+--------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+--------------------+---------------------+-------+---------------+---------+---------+------+------+--------------------------+ | 1 | PRIMARY | t_cmdb_app_version | index | NULL | PRIMARY | 4 | NULL | 659 | Using where; Using index | | 2 | DEPENDENT SUBQUERY | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | Using where | | 3 | DEPENDENT UNION | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | Using where | | NULL | UNION RESULT || ALL | NULL | NULL | NULL | NULL | NULL | Using temporary | +----+--------------------+---------------------+-------+---------------+---------+---------+------+------+--------------------------+ 4 rows in set (0.00 sec)
MySQL [xxuer]> explain SELECT -> count(*) -> FROM -> t_cmdb_app_version a -> INNER JOIN -> (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation) b ON a.id = b.pid; +----+--------------+---------------------+--------+---------------+---------+---------+-------+------+--------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+--------------+---------------------+--------+---------------+---------+---------+-------+------+--------------------------+ | 1 | PRIMARY || ALL | NULL | NULL | NULL | NULL | 766 | Using where | | 1 | PRIMARY | a | eq_ref | PRIMARY | PRIMARY | 4 | b.pid | 1 | Using where; Using index | | 2 | DERIVED | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | NULL | | 3 | UNION | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | NULL | | NULL | UNION RESULT | | ALL | NULL | NULL | NULL | NULL | NULL | Using temporary | +----+--------------+---------------------+--------+---------------+---------+---------+-------+------+--------------------------+ 5 rows in set (0.00 sec)
以上就是mysql 优化中如何进行IN换INNER JOIN,小编相信有部分知识点可能是我们日常工作会见到或用到的。希望你能通过这篇文章学到更多知识。更多详情敬请关注创新互联行业资讯频道。
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