python代码实现2048游戏-创新互联
python代码实现2048游戏?相信很多没有经验的人对此束手无策,为此本文总结了问题出现的原因和解决方法,通过这篇文章希望你能解决这个问题。
创新互联建站是专业的镇安网站建设公司,镇安接单;提供成都网站设计、网站建设,网页设计,网站设计,建网站,PHP网站建设等专业做网站服务;采用PHP框架,可快速的进行镇安网站开发网页制作和功能扩展;专业做搜索引擎喜爱的网站,专业的做网站团队,希望更多企业前来合作!一、分析与函数设计
1.1 游戏玩法
2048这款游戏的玩法很简单,每次可以选择上下左右滑动,每滑动一次,所有的数字方块都会往滑动的方向靠拢,系统也会在空白的地方乱数出现一个数字方块,相同数字的方块在靠拢、相撞时会相加。(介绍来自百度百科)
1.2 函数设计
_init _() 初始化4*4游戏地图,分数等游戏基本数据
is_gameover() 判断是否结束游戏
rannumber() 玩家每次移动时在地图上随机生成2、4
show() 在控制台打印出4*4游戏地图
print_score() 在控制台打印出当前分数
up(), upmove() 上移
down(), downmove() 下移
left(), leftmove() 左移
right(), rightmove() 右移
nextstep() 读取玩家按键
二、代码实现
注:IDE为Spyder,Python版本为3.6
# -*- coding: utf-8 -*- """ Created on Sat Sep 29 16:29:04 2018 @author: PastoralDog """ import random class game2048(object): def __init__(self): self.score=0 self.number=[[0,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,0]] self.move=0 seed=random.randint(0,15) line=int(seed/4) row=seed%4 self.number[line][row]=2 def is_gameover(self): numbersum=0 for i in range(4): for j in range(4): if (self.number[i][j]!=0): numbersum+=1 if(numbersum!=16): return False for i in range(4): for j in range(3): if(self.number[i][j+1]==self.number[i][j]): return False for i in range(3): for j in range(4): if(self.number[i+1][j]==self.number[i][j]): return False print("游戏结束") print("您的得分为:"+str(self.score)) self.__init__() return True def rannumber(self): rannumber=random.randint(1,10) if(rannumber<=8): rannumber=2 else: rannumber=4 done=0 count=0 for i in range(4): for j in range(4): if(self.number[i][j]==0): count+=1 while(done==0 and count!=0): ranplace=random.randint(0,15) line=int(ranplace/4) row=ranplace%4 if(self.number[line][row]==0): done=1 self.number[line][row]=rannumber def show(self): print(self.number[0]) print(self.number[1]) print(self.number[2]) print(self.number[3]) def print_score(self): print("得分:"+str(self.score)) def upmove(self): for i in range(1,4): for j in range(4): temp=i while(temp>=1 and self.number[temp-1][j]==0): box=self.number[temp-1][j] self.number[temp-1][j]=self.number[temp][j] self.number[temp][j]=box if(self.number[temp][j]!=0):self.move=1 temp-=1 def up(self): self.upmove() for i in range(1,4): for j in range(4): if(self.number[i-1][j]==self.number[i][j]): if(self.number[i-1][j]!=2048): self.score+=self.number[i][j] self.number[i][j]=0 self.number[i-1][j]=2*self.number[i-1][j] self.upmove() if(self.move!=0):self.rannumber() self.move=0 self.show() self.is_gameover() self.print_score() def downmove(self): for i in range(2,-1,-1): for j in range(4): temp=i while(temp<=2 and self.number[temp+1][j]==0 ): box=self.number[temp+1][j] self.number[temp+1][j]=self.number[temp][j] self.number[temp][j]=box if(self.number[temp+1][j]!=0):self.move=1 temp+=1 def down(self): self.downmove() for i in range(2,-1,-1): for j in range(4): if(self.number[i+1][j]==self.number[i][j]): if(self.number[i+1][j]!=2048): self.score+=self.number[i][j] self.number[i][j]=0 self.number[i+1][j]=2*self.number[i+1][j] self.downmove() if(self.move!=0):self.rannumber() self.move=0 self.show() self.is_gameover() self.print_score() def leftmove(self): for i in range(4): for j in range(1,4): temp=j while(temp>=1 and self.number[i][temp-1]==0 ): box=self.number[i][temp-1] self.number[i][temp-1]=self.number[i][temp] self.number[i][temp]=box if(self.number[i][temp-1]!=0):self.move=1 temp-=1 def left(self): self.leftmove() for i in range(4): for j in range(0,3): if(self.number[i][j+1]==self.number[i][j]): if(self.number[i][j+1]!=2048): self.score+=self.number[i][j] self.number[i][j+1]=0 self.number[i][j]=2*self.number[i][j] self.leftmove() if(self.move!=0):self.rannumber() self.move=0 self.show() self.is_gameover() self.print_score() def rightmove(self): for i in range(4): for j in range(2,-1,-1): temp=j while(temp<=2 and self.number[i][temp+1]==0 ): box=self.number[i][temp+1] self.number[i][temp+1]=self.number[i][temp] self.number[i][temp]=box self.move=1 temp+=1 def right(self): self.rightmove() for i in range(4): for j in range(2,-1,-1): if(self.number[i][j+1]==self.number[i][j]): if(self.number[i][j+1]!=2048): self.score+=self.number[i][j] self.number[i][j]=0 self.number[i][j+1]=2*self.number[i][j+1] self.rightmove() if(self.move!=0):self.rannumber() self.move=0 self.show() self.is_gameover() self.print_score() def nextstep(self,step): if(step=='w'): self.up() elif(step=='s'): self.down() elif(step=='a'): self.left() elif(step=='d'): self.right() else: pass if __name__ == '__main__': game=game2048() game.show() while(True): step=input() if(step=='b'):break game.nextstep(step)
三、问题与解决方案
1.地图的储存与表示:目前没有界面设计,因此就用二维数组直接储存与表示
2.数组越界:调试代码中遇到过五六次,除了牢记要边缘检测外, and 语句左右条件顺序也要有讲究。
例:while(temp<=2 and self.number[temp+1][j]==0 ) 注:self.number为4*4的二维数组
当temp=3时,语句在temp<=2 被阻塞,不会执行self.number[temp+1][j]==0,此时没有问题;
若语句改为while(self.number[temp+1][j]==0 and temp<=2), 先执行self.number[temp+1][j]==0,此时编译器报错数组越界
看完上述内容,你们掌握python代码实现2048游戏的方法了吗?如果还想学到更多技能或想了解更多相关内容,欢迎关注创新互联行业资讯频道,感谢各位的阅读!
本文题目:python代码实现2048游戏-创新互联
当前链接:http://azwzsj.com/article/hpsod.html