C++线索化二叉树
二叉树是一种非线性结构,遍历二叉树几乎都是通过递归或者用栈辅助实现非递归的遍历。用二叉树作为存储结构时,取到一个节点,只能获取节点的左孩子和右孩子,不能直接得到节点的任一遍历序列的前驱或者后继。为了保存这种在遍历中需要的信息,我们利用二叉树中指向左右子树的空指针来存放节点的前驱和后继信息。
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#includeusing namespace std; enum PointerTag {THREAD, LINK}; template struct BinaryTreeNodeThd { T _data; //数据 BinaryTreeNodeThd * _left; //左孩子 BinaryTreeNodeThd * _right; //右孩子 PointerTag _leftTag; //左孩子线索标志 PointerTag _rightTag; //右孩子线索标志 BinaryTreeNodeThd(const T& data) :_data(data) ,_left(NULL) ,_right(NULL) ,_leftTag(LINK) ,_rightTag(LINK) {} }; template class BinaryTreeThd { public: BinaryTreeThd(const T* array, size_t size, const T& invalid) { size_t index = 0; _root = _CreateTree(array, size, index, invalid); } ~BinaryTreeThd() { _DestroyTree(_root); _root = NULL; } void InOrderThreading() { BinaryTreeNodeThd * prev = NULL; _InOrderThreading(_root, prev); } void PreOrderThreading() { BinaryTreeNodeThd * prev = NULL; _PreOrderThreading(_root, prev); } void PostOrderThreading() { BinaryTreeNodeThd * prev = NULL; _PostOrderThreading(_root, prev); } void PreOrderThd() { BinaryTreeNodeThd * cur = _root; while (cur) { while (cur && LINK == cur->_leftTag) { cout< _data<<" "; cur = cur->_left; } cout< _data<<" "; cur = cur->_right; } cout< * cur = _root; while (cur) { while (cur && LINK == cur->_leftTag) { cur = cur->_left; } cout< _data<<" "; while (THREAD == cur->_rightTag) { cur = cur->_right; cout< _data<<" "; } cur = cur->_right; } cout< * _CreateTree(const T* array, size_t size, size_t& index, const T& invalid) { BinaryTreeNodeThd * root = NULL; if (index < size && array[index] != invalid) { root = new BinaryTreeNodeThd (array[index]); root->_left = _CreateTree(array, size, ++index, invalid); root->_right = _CreateTree(array, size, ++index, invalid); } return root; } void _DestroyTree(BinaryTreeNodeThd * root) { if (NULL == root) return; if (LINK == root->_leftTag) _DestroyTree(root->_left); if (LINK == root->_rightTag) _DestroyTree(root->_right); delete root; } void _PreOrderThreading(BinaryTreeNodeThd * cur, BinaryTreeNodeThd *& prev) { if (NULL == cur) return; if (NULL == cur->_left) { cur->_leftTag = THREAD; cur->_left = prev; } if (prev && NULL == prev->_right) { prev->_rightTag = THREAD; prev->_right = cur; } prev = cur; if (cur->_leftTag == LINK) _PreOrderThreading(cur->_left, prev); if (cur->_rightTag == LINK) _PreOrderThreading(cur->_right, prev); } void _InOrderThreading(BinaryTreeNodeThd * cur, BinaryTreeNodeThd *& prev) { if (NULL == cur) return; _InOrderThreading(cur->_left, prev); if (NULL == cur->_left) { cur->_leftTag = THREAD; cur->_left = prev; } if (prev && NULL == prev->_right) { prev->_rightTag = THREAD; prev->_right = cur; } prev = cur; _InOrderThreading(cur->_right, prev); } void _PostOrderThreading(BinaryTreeNodeThd * cur, BinaryTreeNodeThd *& prev) { if (NULL == cur) return; _PostOrderThreading(cur->_left, prev); _PostOrderThreading(cur->_right, prev); if (cur->_left == NULL) { cur->_leftTag = THREAD; cur->_left = prev; } if (prev && NULL == prev->_right) { prev->_rightTag = THREAD; prev->_right = cur; } prev = cur; } protected: BinaryTreeNodeThd * _root; }; void Test() { int a[] = {1, 2, 3, '#', '#', 4, '#', '#', 5, 6}; BinaryTreeThd t1(a, sizeof(a)/sizeof(a[0]), '#'); t1.PreOrderThreading(); t1.PreOrderThd(); BinaryTreeThd t2(a, sizeof(a)/sizeof(a[0]), '#'); t2.InOrderThreading(); t2.InOrderThd(); int a1[] = {1, 2, '#', 3, '#', '#', 4, 5, '#', 6, '#', 7, '#', '#', 8}; BinaryTreeThd t3(a1, sizeof(a1)/sizeof(a1[0]), '#'); t3.PreOrderThreading(); t3.PreOrderThd(); } int main() { Test(); return 0; }
本文题目:C++线索化二叉树
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