JavaScript浮点数及其运算-创新互联
Math.pow(底数,几次方)
Number.toFixed(小数位数)
2.浮点数相加
function
accAdd(arg1,arg2){
var
r1,r2,m;
try
{r1=arg1.toString().split(
"."
)[1].length}
catch
(e){r1=0}
try
{r2=arg2.toString().split(
"."
)[1].length}
catch
(e){r2=0}
m=Math.pow(10,Math.max(r1,r2))
return
(arg1*m+arg2*m)/m
}
3.浮点数相减
function
accSub(arg1,arg2){
var
r1,r2,m,n;
try
{r1=arg1.toString().split(
"."
)[1].length}
catch
(e){r1=0}
try
{r2=arg2.toString().split(
"."
)[1].length}
catch
(e){r2=0}
m=Math.pow(10,Math.max(r1,r2));
//last modify by deeka
//动态控制精度长度
n=(r1>=r2)?r1:r2;
return
((arg1*m-arg2*m)/m).toFixed(n);
}
4.浮点数相除
function
accDiv(arg1,arg2){
var
t1=0,t2=0,r1,r2;
try
{t1=arg1.toString().split(
"."
)[1].length}
catch
(e){}
try
{t2=arg2.toString().split(
"."
)[1].length}
catch
(e){}
with
(Math){
r1=Number(arg1.toString().replace(
"."
,
""
))
r2=Number(arg2.toString().replace(
"."
,
""
))
return
(r1/r2)*pow(10,t2-t1);
}
}
5.浮点数相乘
function
accMul(arg1,arg2) {
var
m=0,s1=arg1.toString(),s2=arg2.toString();
try
{m+=s1.split(
"."
)[1].length}
catch
(e){}
try
{m+=s2.split(
"."
)[1].length}
catch
(e){}
return
Number(s1.replace(
"."
,
""
))*Number(s2.replace(
"."
,
""
))/Math.pow(10,m)
}
测试:
console.log(accAdd(1.79, 0.12));
//1.91
console.log(accSub(2.01, 0.12));
//1.89
console.log(accDiv(0.69, 10));
//0.069
console.log(accMul(1.01, 1.3)); //1.313
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