java初期的敲代码题 java新手代码大全
一道Java编程题目，新手求详细代码
import java.io.BufferedReader;
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import java.io.IOException;
import java.io.InputStreamReader;
public class _1 {
/**
* @param args
* @throws IOException
*/
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
String zifuchuan = new String("");
int hanzishu = 0;
int zimu = 0;
int kongge = 0;
int shuzi = 0;
int qita = 0;
System.out.print("请输入一行字符：");
BufferedReader stdin = new BufferedReader(new InputStreamReader(
System.in));
zifuchuan = stdin.readLine();
byte[] bytes = zifuchuan.getBytes();
for (int i = 0; i bytes.length; i++) {
if ((bytes[i] = 65 bytes[i] = 90)
|| (bytes[i] = 97 bytes[i] = 122))
zimu++;
else if (bytes[i] == 32)
kongge++;
else if (bytes[i] = 48 bytes[i] = 57)
shuzi++;
else if (bytes[i] 0)
hanzishu++;
else
qita++;
}
System.out.println("字符串所占字节个数为：" + bytes.length);
System.out.println("汉字个数为：" + hanzishu / 2);
System.out.println("英文字母个数为：" + zimu);
System.out.println("空格个数为：" + kongge);
System.out.println("数字个数为：" + shuzi);
System.out.println("其他字符个数为：" + qita);
}
}
JAVA敲代码..求教 作业题..
这个题目，考查你对数组结构、操作的了解
数组在内存中，是一组“长度固定的（创建以后就不可修改）、地址相邻的内存空间”，比如三个元素的数组
String[] array = {"1","2","3"};其内存结构
--------
| 1 |
--------
--------
| 2 |
--------
--------
| 3 |
--------
如果我要在第2个位置插入数据，则需要：
1、修改数组长度
2、将2、3向下移一个位置，空出一个给“ddd”
下面是实现代码
public static void main(String[] args) {
String[] array = { "1", "2", "3" };
array = insert(array, "ddd", 2);
for (int i = 0; i array.length; i++) {
System.out.print(array[i] + " ");
}
}
/**
* 在数组array的第index个位置，播放元素value,并返回该数组
*/
public static String[] insert(String[] array, String value, int index) {
//因为数组是“固定长度”，所以，必须要使用一个新的数组
String[] newArray = new String[array.length + 1];
int count = 0;
//将旧数组+插值得到新数组
for (int i = 0; i array.length; i++) {
if ((i + 1) == index) {
newArray[count++] = "ddd";
}
newArray[count++] = array[i];
}
return newArray;
}
Java入门编程题 求大佬帮忙解答一下 请附上代码和运行截图
public static void printMax(){
int[][] ay = {{22,91,0,5},{33,21},{19,-1,28,88}};
ListInteger list = new ArrayList();
for (int[] x:ay){
for (int y:x){
list.add(y);
}
}
System.out.println(Collections.max(list));
}
public static void main(String[] args) {
printMax();
}
JAVA初级编程题 求代码
public class Doctor {
private String name;
private int idNumber;
private String address;
public Doctor(String name, int idNumber, String address) {
super();
this.name = name;
this.idNumber = idNumber;
this.address = address;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
public int getIdNumber() {
return idNumber;
}
public void setIdNumber(int idNumber) {
this.idNumber = idNumber;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String toString(){
return this.name+":"+this.idNumber+":"+this.address;
}
public static void main(String[] args) {
Doctor d1=new Doctor("cyq",10,"nanjin road shanghai");
NonSpecialist d2=new NonSpecialist("jr",11,"sichuan road shanghai");
Specialist d3=new Specialist("xyz",12,"beijin road shanghai");
d3.setSpecialty("medical ");
System.out.println(d1);
System.out.println(d2);
System.out.println(d3);
}
}
class NonSpecialist extends Doctor{
public NonSpecialist(String name, int idNumber, String address) {
super(name, idNumber, address);
}
}
class Specialist extends Doctor{
private String specialty;
public Specialist(String name, int idNumber, String address) {
super(name, idNumber, address);
}
public String getSpecialty() {
return specialty;
}
public void setSpecialty(String specialty) {
this.specialty = specialty;
}
@Override
public String toString() {
return super.toString()+":"+this.specialty;
}
}
好了，这样应该可以了
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