小编这次要给大家分享的是python如何实现mask矩阵，文章内容丰富，感兴趣的小伙伴可以来了解一下，希望大家阅读完这篇文章之后能够有所收获。

创新互联不只是一家网站建设的网络公司；我们对营销、技术、服务都有自己独特见解，公司采取“创意+综合+营销”一体化的方式为您提供更专业的服务！我们经历的每一步也许不一定是最完美的，但每一步都有值得深思的意义。我们珍视每一份信任，关注我们的成都网站制作、做网站质量和服务品质，在得到用户满意的同时，也能得到同行业的专业认可，能够为行业创新发展助力。未来将继续专注于技术创新，服务升级，满足企业一站式营销型网站建设需求，让再小的成都品牌网站建设也能产生价值！

代码实现

def generateMaskBasedOnDom(dom_path, length):
  """
  :param dom_path: this is a file path, which contains the following information:
  [7-56,239-327,438-454,522-556,574-586][57-85,96-112,221-238][113-220,328-437,455-521,557-573]
  each [...] means one domain
  :param length: this is the length of this protein
  :return: the mask matrix with size length x length, 1 means inner domain residue pair, otherwise 0
  """
  # 读取文件
  with open(dom_path, "r", encoding="utf-8") as file:
    contents = file.readlines()

  # 获得mask位置数据
  list0 = []
  list1 = []
  list2 = []
  for list_idx, content in enumerate(contents):
    num_range_list = content.strip()[1:-1].split(",")
    for num_range in num_range_list:
      start_num = int(num_range.split("-")[0])
      end_num = int(num_range.split("-")[1])
      for num in range(start_num, end_num+1):
        if list_idx == 0:
          list0.append(num)
        elif list_idx == 1:
          list1.append(num)
        else:
          list2.append(num)

  mask = np.zeros((length, length))
  # 遍历矩阵每个元素
  for row in range(mask.shape[0]):
    for col in range(mask.shape[1]):
      if (row in list0 and col in list0) or (row in list1 and col in list1) or (row in list2 and col in list2):
        mask[row][col] = 1

  return mask

if __name__ == "__main__":

  # if no dom file ,please get dom file first
  with open("dom.txt", "w", encoding="utf-8") as f:
    f.write("[7-56,239-327,438-454,522-556,574-586]" + "\n" + "[57-85,96-112,221-238]" + "\n" + "[113-220,328-437,455-521,557-573]")

  file_path = "./dom.txt"
  protein_length = 1000  # mask_matrix size
  mask_matrix = generateMaskBasedOnDom(file_path, protein_length)
  print("*************Generate Mask Matrix Successful!*************")

  # 随机测试几组
  print(mask_matrix[7][56]) # 1
  print(mask_matrix[7][239]) # 1
  print(mask_matrix[8][57])  # 0
  print(mask_matrix[57][95]) # 0
  print(mask_matrix[113][573]) # 1

分享标题：python如何实现mask矩阵-创新互联
文章出自：http://azwzsj.com/article/djphho.html