c语言如何实现玫瑰花
c语言实现玫瑰花的方法:首先定义全局变量,并定义结构体;然后设置输出花柄、花柄、绿叶、花萼;最后创建绘图窗口,输出完整花朵。
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c语言实现玫瑰花的方法:
#include#include ? #include #include #include #pragma comment(lib,"winmm.lib") //定义全局变量 int rosesize = 500; int h = -250; //定义结构体 struct DOT { double x; double y; double z; double r; double g; }; bool calc(double a,double b,double c,DOT &d) { double j, n, o, w, z; if (c > 60) { //花柄 d.x = sin(a * 7)*(13 + 5 / (0.2 + pow(b * 4, 4))) - sin(b) * 50; d.y = b*rosesize + 50; d.z = 625 + cos(a * 7)*(13 + 5 / (0.2 + pow(b * 4, 4))) + b * 400; d.r = a * 1 - b / 2; d.g = a; return true; } double A = a * 2 - 1; double B = b * 2 - 1; if (A*A + B*B < 1) { //绿叶 if (c > 37) { j = (int(c) & 1); n = j ? 6 : 4; o = 0.5 / (a + 0.01) + cos(b * 125) * 3 - a * 300; w = b * h; d.x = o * cos(n) + w * sin(n) + j * 610 - 390; d.y = o * sin(n) - w * cos(n) + 550 - j * 350; d.z = 1180 + cos(B + A) * 99 - j * 300; d.r = 0.4 - a * 0.1 + pow(1 - B * B, -h * 6) * 0.15 - a * b * 0.4 + cos(a + b) / 5 + pow(cos((o * (a + 1) + (B > 0 ? w : -w)) / 25), 30) * 0.1 * (1 - B * B); d.g = o / 1000 + 0.7 - o * w * 0.000003; return true; } if (c > 32) { //花萼 c = c*1.16 - 0.15; o = a * 45 - 20; w = b * b * h; z = o * sin(c) + w * cos(c) + 620; d.x = o * cos(c) - w * sin(c); d.y = 28 + cos(B * 0.5) * 99 - b * b * b * 60 - z / 2 - h; d.z = z; d.r = (b * b * 0.3 + pow((1 - (A * A)), 7)*0.15 + 0.3)*b; d.g = b * 0.7; return true; } //花朵 o = A*(2 - b)*(80 - c * 2); w = 99 - cos(A) * 120 - cos(b)*(-h - c * 4.9) + cos(pow(1 - b, 7)) * 50 + c * 2; z = o * sin(c) + w * cos(c) + 700; d.x = o * cos(c) - w * sin(c); d.y = B * 99 - cos(pow(b, 7)) * 50 - c / 3 - z / 1.35 + 450; d.z = z; d.r = (1 - b / 1.2) * 0.9 + a * 0.1; d.g = pow((1 - b), 20) / 4 + 0.05; return true; } return false; } int main() { short ?*zBuffer; int x, y, z, zBufferIndex; DOT dot; initgraph(640,480);//创建绘图窗口 /*添加音乐*/ mciSendString("open BadApple.mp3 alias BadApple", NULL, 0, NULL); mciSendString("play BAdApple", NULL, 0, NULL); setbkcolor(YELLOW); cleardevice(); zBuffer = new short[rosesize * rosesize]; memset(zBuffer, 0, sizeof(short) * rosesize * rosesize); for (int j = 0; j < 2000; j++)// && !_kbhit() { for (int i = 0; i < 10000; i++) if (calc(double(rand()) / RAND_MAX, double(rand()) / RAND_MAX, rand() % 46 / 0.74, dot)) { z = int(dot.z + 0.5); x = int(dot.x*rosesize / z - h + 0.5); y = int(dot.y*rosesize / z - h + 0.5); if (y > rosesize) continue; zBufferIndex = y*rosesize + x; if (!zBuffer[zBufferIndex] || zBuffer[zBufferIndex] > z) { zBuffer[zBufferIndex] = z; //画点 int r = ~int((dot.r*h)); ? if (r < 0)r = 0; ? if (r > 255)r = 255; int g = ~int((dot.g*h)); if (g < 0)g = 0; if (g > 255)g = 255; int b = ~int((dot.r*dot.r*-80)); if (b < 0)b = 0; if (b > 255)b = 255; putpixel(x + 50, y - 20, RGB(r, g, b)); } } Sleep(100); } delete[]zBuffer; getchar(); closegraph(); return 0; }
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文章名称:c语言如何实现玫瑰花
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