三子棋你值得拥有(已优化可实现N子棋)-创新互联
文章目录
一、三子棋的实现所需文件 1.
本文题目:三子棋你值得拥有(已优化可实现N子棋)-创新互联
本文网址:http://azwzsj.com/article/cesoeh.html
- 一、三子棋的实现所需文件
- 1.
- 2.
- 3.
- 1.
- 二、三子棋游戏函数(已优化)
- 1.test()
- 2.menu()
- 3.inti_board(board,ROW,COL)
- 4.print_board(board, ROW, COL)
- 5.player_move(board, ROW, COL)
- 6.computer_move(board, ROW, COL);
- 7.is_win(board, ROW, COL)//该函数已优化可以实现N×N子棋;
- 8.is_full(board, ROW, COL)
- 三. 学习鸡汤
一、三子棋的实现所需文件 1.
#include "add.h"
void game()
{
char ret=0;
char board[ROW][COL];
inti_board(board,ROW,COL);
print_board(board, ROW, COL);
while(1)
{
player_move(board, ROW, COL);//玩家下棋
print_board(board, ROW, COL);//打印棋盘
ret = is_win(board, ROW, COL);//判断输赢
if (ret != 'c')
{
break;
}
computer_move(board, ROW, COL);
print_board(board, ROW, COL);
ret = is_win(board, ROW, COL);
if (ret != 'c')
{
break;
}
}
if (ret == '#')
printf("电脑赢了\n");
else if (ret == '*')
printf("玩家赢了\n");
else if (ret == 'Q')
printf("平局\n");
}
void menu()
{
printf("****************\n");
printf("** 1.play ***\n");
printf("** 0.exit ***\n");
printf("****************\n");
}
void test()
{
srand((unsigned)time(NULL));
int a = 0;
do
{
menu();
printf("请选择\n");
scanf("%d", &a);
switch (a)
{
case 1: printf("三子棋\n");
game();
break;
case 2: printf("退出游戏\n");
break;
default:printf("重新选择\n");
}
} while (a);
}
int main()
{
int a = 0;
test();
return 0;
}
2.#include "add.h";
void inti_board(char board[ROW][COL], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i< row; i++)
{
for (j = 0; j< col; j++)
{
board[i][j]=' ';
}
}
}
void print_board(char board [ROW] [COL], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i< row; i++)
{
for (j = 0; j< col; j++)
{
printf(" %c ", board[i][j]);
if (j< col-1)
printf("|");
}
printf("\n");
if (i< row - 1)
for (j = 0; j< col; j++)
{
printf("---");
if (j< col-1)
printf("|");
}
printf("\n");
}
}
void player_move(char board[ROW][COL], int row, int col)
{
printf("玩家下棋\n");
while (1)
{
printf("请输入坐标\n");
int x, y;
scanf("%d %d", &x, &y);
if (x - 1 >= 0 && x - 1< row && y - 1< col && y - 1 >= 0)
{
if (board[x - 1][y - 1] == ' ')
{
board[x - 1][y - 1] = '*';
break;
}
else
printf("该坐标已被占用,请重新输入\n");
}
else
printf("非法坐标重新输入\n");
}
}
void computer_move(char board[ROW][COL], int row, int col)
{
printf("电脑输入\n");
while (1)
{
int x = rand() % row;
int y = rand() % col;
if (board[x ][y ] == ' ')
{
board[x][y] = '#';
break;
}
}
}
int is_full(char board[ROW][COL], int row, int col)
{
int i = 0;
for (i = 0; i< row; i++)
{
int j = 0;
for (j = 0; j< col; j++)
{
if (board[i][j] == ' ')
return 0;
}
}
return 1;
}
char is_win(char board[ROW][COL], int row, int col)
{
int flag = 0;
int i = 0;
int j = 0;
for (i = 0; i< row; i++)
{
flag = 0;
for (j = 1; j< col; j++)
{
if (board[i][j - 1] == board[i][j] && board[i][j - 1] != ' ' && board[i][j] != ' ')
{
flag++ ;
}
}
if (flag == col - 1)
return board[i][j - 1];
}
flag = 0;
for (j = 0; j< col; j++)
{
flag = 0;
for ( i= 1; i< row; i++)
{
if (board[i - 1][j] == board[i][j] && board[i - 1][j] != ' ' && board[i - 1][j] != ' ')
flag ++;
}
if (flag == row - 1)
return board[i-1][j];
}
flag = 0;
for (i = 0; i< row-1; i++)
{
if (board[i][i] != board[i + 1][i + 1] || board[i][i] == ' ' || board[i + 1][i + 1] == ' ')
{
flag = 1;
}
}
if (flag == 0)
return board [i-1][i-1];
flag = 0;
for (i = 1; i< row; i++)
{
if (board[i-1][row - 1-(i-1) ] != board[i ][row-i-1] || board[i-1][row - 1 -(i-1)] == ' ' || board[i] [row-i-1]== ' ')
flag = 1;
}
if(flag==0)
return board[row-1][0];
if (is_full(board, ROW, COL) == 1)
{
return 'Q';
}
return 'c';
}
3.#define _CRT_SECURE_NO_WARNINGS
#define ROW 3
#define COL 3
#include#include#includevoid inti_board(char board[ROW][COL], int row, int col);//小写因为不与ROW COL冲突
void print_board(char board[ROW][COL],int row,int col);
void player_move(char board[ROW][COL], int row, int col);
void computer_move(char board[ROW][COL], int row, int col);
char is_win(char board[ROW][COL], int row, int col);
二、三子棋游戏函数(已优化)
1.test()#define _CRT_SECURE_NO_WARNINGS
#define ROW 3//N子棋
#define COL 3//
#include#include#includevoid inti_board(char board[ROW][COL], int row, int col);//小写因为不与ROW COL冲突
void print_board(char board[ROW][COL],int row,int col);
void player_move(char board[ROW][COL], int row, int col);
void computer_move(char board[ROW][COL], int row, int col);
char is_win(char board[ROW][COL], int row, i
void test()//选择游戏是否开始与结束
{
srand((unsigned)time(NULL));//该函数为库函数且不能多次使用,用于电脑随机生成数字
int a = 0;
do
{
menu();
printf("请选择\n");
scanf("%d", &a);
switch (a)
{
case 1: printf("三子棋\n");
game();
break;
case 2: printf("退出游戏\n");
break;
default:printf("重新选择\n");
}
} while (a);
}
2.menu()void menu()//给用户观看的菜单
{
printf("****************\n");
printf("** 1.play ***\n");
printf("** 0.exit ***\n");
printf("****************\n");
}
3.inti_board(board,ROW,COL)void inti_board(char board[ROW][COL], int row, int col)//给棋盘初始化
{
int i = 0;
int j = 0;
for (i = 0; i< row; i++)
{
for (j = 0; j< col; j++)
{
board[i][j]=' ';
}
}
}
4.print_board(board, ROW, COL)void print_board(char board [ROW] [COL], int row, int col)//打印该棋盘
{
int i = 0;
int j = 0;
for (i = 0; i< row; i++)
{
for (j = 0; j< col; j++)
{
printf(" %c ", board[i][j]);
if (j< col-1)//每行最后一列不用打印分割行
printf("|");
}
printf("\n");
if (i< row - 1)//最后一行不用打印分割行
for (j = 0; j< col; j++)
{
printf("---");
if (j< col-1)//每行最后一列不用打印分割行
printf("|");
}
printf("\n");
}
}
图片:
5.player_move(board, ROW, COL)void player_move(char board[ROW][COL], int row, int col)//玩家下棋
{
printf("玩家下棋\n");
while (1)
{
printf("请输入坐标\n");
int x, y;
scanf("%d %d", &x, &y);
if (x - 1 >= 0 && x - 1< row && y - 1< col && y - 1 >= 0)//在合法坐标内才可下棋
{
if (board[x - 1][y - 1] == ' ')//判断该坐标是否有棋
{
board[x - 1][y - 1] = '*';//玩家下棋
break;
}
else
printf("该坐标已被占用,请重新输入\n");
}
else
printf("非法坐标重新输入\n");
}
}
6.computer_move(board, ROW, COL);void computer_move(char board[ROW][COL], int row, int col)//电脑下棋
{printf("电脑输入\n");
while (1)
{int x = rand() % row;//该函数为库函数随机生成坐标
int y = rand() % col;
if (board[x ][y ] == ' ')
{ board[x][y] = '#';//电脑下棋
break;
}
}
}
7.is_win(board, ROW, COL)//该函数已优化可以实现N×N子棋;char is_win(char board[ROW][COL], int row, int col)//判断是否输赢,返回值为一个字符
{
int flag = 0;
int i = 0;
int j = 0;
for (i = 0; i< row; i++)//共row行
{
flag = 0;
for (j = 1; j< col; j++)//对比col-1次
{
if (board[i][j - 1] == board[i][j] && board[i][j - 1] != ' ' && board[i][j] != ' ')//判断一行中左右坐标是否相等且是否为空
{
flag++ ;//如果前后坐标相等且不是空坐标则加1
}
}
if (flag == col - 1)//共对比col-1次,如果flag加了col-1次说明一行中坐标全都相等且不为空坐标
return board[i][j - 1];返回该坐标的字符
}
//(同上思路)
flag = 0;//重新赋值
for (j = 0; j< col; j++)//循环col次
{
flag = 0;
for ( i= 1; i< row; i++)//外循环一次内循环row-1次
{
if (board[i - 1][j] == board[i][j] && board[i - 1][j] != ' ' && board[i - 1][j] != ' ')//判断一列中上下坐标是否相等,且是否为空
flag ++;//如果上下坐标相等且不是空坐标则加1
}
if (flag == row - 1)//共对比row-1次,如果flag加了row-1次说明一列中坐标全都相等且不为空坐标
return board[i-1][j];返回该坐标的字符
}
flag = 0;
for (i = 0; i< row-1; i++)
{
if (board[i][i] != board[i + 1][i + 1] || board[i][i] == ' ' || board[i + 1][i + 1] == ' ')//从左上到右下对角线的两两对比
{
flag = 1;
}
}
if (flag == 0)
return board [i-1][i-1];
flag = 0;
for (i = 1; i< row; i++)
{
if (board[i-1][row - 1-(i-1) ] != board[i ][row-i-1] || board[i-1][row - 1 -(i-1)] == ' ' || board[i] [row-i-1]== ' ')//从右上到左下的两两对比
flag = 1;//如果其中有一个对比失败flag为1
}
if(flag==0)//说明row-1次对比都相等且不为空坐标
return board[row-1][0];
if (is_full(board, ROW, COL) == 1)//在玩家和电脑都没赢的情况下,该函数判断棋盘受否满了,因为该函数为is_win所使用,所以不用在中声明
{
return 'Q';
}
return 'c';
}
图片:
图片:
8.is_full(board, ROW, COL)int is_full(char board[ROW][COL], int row, int col)//判断棋盘是否满了
{
int i = 0;
for (i = 0; i< row; i++)
{
int j = 0;
for (j = 0; j< col; j++)
{
if (board[i][j] == ' ')//如果有一个空坐标返回0
return 0;
}
}
return 1;
}
三. 学习鸡汤每个人都有完美的梦想,只有坚持,你的梦想才能实现,
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本文题目:三子棋你值得拥有(已优化可实现N子棋)-创新互联
本文网址:http://azwzsj.com/article/cesoeh.html